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jmc

prealgebra senior

Problem

Eighty percent of the students in a class (group A) share of the candy equally. The remaining of the students (group B) share the other of the candy equally. The ratio of the amount of candy a student in group A has to the amount of candy a student in group B has is equal to what common fraction?
Solution
Suppose that there are pieces of candy total shared by students in the class. In group A, there are students sharing pieces of candy. Dividing the two, we have , or pieces of candy per student. In group B, there are students sharing pieces of candy. Dividing the two, we have , or pieces of candy per student. The ratio between the pieces of candy per student in group A and that in group B is .
Final answer
\frac{1}{6}