Let x=(5+1)(\root4\of5+1)(\root8\of5+1)(\root16\of5+1)4.Find (x+1)48.
Solution — click to reveal
Multiplying the top and bottom by 165−1, we get a lot of simplification by difference-of-squares: x=(5+1)(45+1)(85+1)(165+1)(165−1)4(165−1)=(5+1)(45+1)(85+1)(85−1)4(165−1)=(5+1)(45+1)(45−1)4(165−1)=(5+1)(5−1)4(165−1)=44(165−1)=165−1.Thus, (x+1)48=(165)48=53=125.