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jmc

number theory junior

Problem

Convert

320 6_{7}

to a base 10 integer.

Solution

320 6_{7} = 3 \cdot 7^{3} + 2 \cdot 7^{2} + 0 \cdot 7^{1} + 6 \cdot 7^{0} = 1029 + 98 + 6 = 1133

.

Final answer

1133