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jmc

prealgebra intermediate

Problem

Square A has side lengths each measuring inches. Square B has side lengths each measuring inches. What is the ratio of the area of the smaller square to the area of the larger square? Express your answer as a common fraction.
Solution
The area of the smaller square is square inches. The area of the larger square is square inches. The ratio of the areas is .
Final answer
\frac{1}{16}