jmc

Let the radius and height of the cylinder measure $r$ and $h$ inches respectively. From the lateral surface area and volume values, we set up the equations $$2\pi rh=24\pi$$ and $$\pi r^{2}h=24\pi .$$ These equations simplify to $rh=12$ and $r^{2}h=24$; it follows that $r=(r^{2}h)/(rh)=24/12=\boxed{2}$ inches.