Browse · MATH Print → jmc algebra junior Problem Evaluate (5a2−13a+4)(2a−3) for a=121. Solution — click to reveal We have a=121=23. When a=23, we find 2a−3=2⋅23−3=3−3=0, so the given expression equals 5a2−13a+4 times 0, which is 0. Final answer 0 ← Previous problem Next problem →