In right triangle ABC with A = 90^, we have AB = 6 and BC = 10. Find A.

Since A = 90^, we have A = 90^= 0.

jmc

geometry intermediate

Problem

In right triangle

A B C

with

∠ A = 9 0^{\circ}

, we have

A B = 6

and

B C = 10

. Find

cos A

Solution

Since

∠ A = 9 0^{\circ}

, we have

cos A = cos 9 0^{\circ} = 0

Final answer