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Print42nd Balkan Mathematical Olympiad
geometry
Problem
Let be an acute-angled triangle with orthocenter and let be an arbitrary point on side . Let and be the points on the segments and respectively such that the quadrilaterals and are cyclic, and let segments and intersect at . Let be the intersection point of line and the tangent to the circumcircle of triangle at point . If lines and intersect at , prove that lies on the line .

Solution
We have and , therefore meaning that is cyclic.
We also have showing that is cyclic. Then, using that is also cyclic, we have Let be the point of intersection of with the circumcircle of . Then showing that belongs on .
Finally, applying Pascal's theorem on the hexagon , we get that , and are collinear, as required.
We also have showing that is cyclic. Then, using that is also cyclic, we have Let be the point of intersection of with the circumcircle of . Then showing that belongs on .
Finally, applying Pascal's theorem on the hexagon , we get that , and are collinear, as required.
Techniques
Triangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circleCyclic quadrilateralsTangentsAngle chasing