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algebra intermediate

Problem

A sequence of positive integers with and is formed so that the first three terms are in geometric progression, the second, third, and fourth terms are in arithmetic progression, and, in general, for all , the terms , , and are in geometric progression, and the terms , , and are in arithmetic progression. Let be the greatest term in this sequence that is less than 1000. Find .
Solution
Let Then the first few terms are and so on.

More generally, we can prove by induction that for any positive integer

Then This simplifies to which factors as Hence,

Then using the formulas above, we can compute that and so the final answer is
Final answer
973