Browse · MATH Print → jmc algebra intermediate Problem Suppose that 4x1=5, 5x2=6, 6x3=7,…,127x124=128. What is x1x2⋯x124? Solution — click to reveal Since 4x1=5, 5x2=6,…,127x124=128, we have 47/2=128=127x124=(126x123)x124=126x123⋅x124=⋯=4x1x2⋯x124.So x1x2⋯x124=27. Final answer \frac{7}{2} ← Previous problem Next problem →