Browse · MATH Print → jmc algebra intermediate Problem Given f(x)=cx3−9x+3 and f(2)=9, find the value of c. Solution — click to reveal Plugging x=2 into the expression for f(x), we find f(2)=c(23)−9(2)+3=8c−18+3=8c−15. Since we know that f(2)=9, f(2)⇒8c−15⇒8c⇒c=9=9=24=3 Final answer 3 ← Previous problem Next problem →