smc

Since the polynomial is quadratic, its second differences must be constant. Taking the first differences, we have $$\begin{array}{rl}3969-3844& =125\\ 4096-3969& =127\\ 4227-4096& =131\\ 4356-4227& =129\\ 4489-4356& =133\\ 4624-4489& =135\\ 4761-4624& =137\end{array}$$ This leads to a common second difference of $2$, with the only discrepancy around the point $4227$. Observe that if this point were instead $4225$, the common second difference would, indeed be $2$ for all data points. Therefore the answer is $4227$, or $\boxed{\text{none of these}}$