Browse · MATH Print → jmc algebra intermediate Problem Expand (x22−3x5+x−2−7)⋅(5x4). Solution — click to reveal Using the distributive property, we can expand this to get (x22−3x5+x−2−7)⋅(5x4)=(x22)(5x4)+(−3x5)(5x4)+(x−2)(5x4)−7(5x4)=5x26−15x9+5x2−35x4=5x26−15x9−35x4+5x2. Final answer 5x^{26}-15x^9-35x^4+5x^2 ← Previous problem Next problem →